Press Release

Home  > Press Release  > 

LED rechargeable flashlight voltage stability principle

LED rechargeable flashlight voltage stability principle

2018-09-16

LED rechargeable flashlight voltage stability principle.The charging voltage of the rechargeable LED flashlight is 3.6V. The service life of a good LED flashlight is closely related to the stability of the voltage. If the voltage is unstable, the flashlight of the flashlight will burn out. This is the same as our previous rural light bulbs. The voltage of the previous home was unstable, and the size of the bulb was reduced. Therefore, we need to consider the voltage stability when designing the LED rechargeable flashlight. Sex, and as soon as possible, the power to achieve continuous stability of the voltage.

LED rechargeable flashlight battery can be directly driven (that is, directly connect the two ends of the battery with wires to the positive and negative terminals of the LED). Most of the LEDs, but the current is unstable, there are large and small, it is easy to cause the LED life to shorten and produce light decay. Therefore, a special circuit for flashlights that control voltage and current was born.

LED flashlight voltage knowledge introduction:

The battery can be driven directly (that is, directly connect the two ends of the battery to the positive and negative terminals of the LED). Most of the LEDs, but the current is unstable, large or small, easy to cause the LED life to shorten, resulting in light decay, so the control voltage A special circuit for flashlights with currents was born.

1, the boost circuit

Mainly used for the flashlight of 18650 lithium battery, because most LEDs work at about 3.6, the lithium battery voltage is 1.2-1.5, the voltage is not enough, and the voltage needs to be raised to 3.6 to make the LED flashlight work normally. Kind of circuit.

2, step-down circuit

Generally used in dual lithium flashlights, such as two 18650 flashlights, LED rechargeable flashlight operating voltage is 3.6, and two 18650 series voltage is about 7.4V, you need to reduce the output voltage of the circuit to 3.6 LED power supply.

3, automatic buck-boost circuit

As the name implies, when the battery voltage is higher than the operating voltage of the LED flashlight, the output voltage is lowered to the working voltage of the LED. When the battery voltage is lower than the operating voltage of the LED flashlight, the output voltage is raised to the working voltage of the LED, thus generating Constant voltage constant current, this is the most ideal circuit.